jika n bilangan bulat maka 2pangkat n+2 dikali 6pangkat n-1 dibagi 12 pangkat n-1=

^ tanda pangkat
2^(n+2) × 6^(n-1) / 12^(n-1)
= 2^n.2^2 × 6^n.6^-1 / 12^n.12^-1
= 2^n.4 × 6^n.(1/6) / 12^n.(1/12)
= (4×(1/6)/(1/12) 2^n × 6^n / 12^n
= (4 × (1/6) × 12) (2×6/12)^n
= 8 (1)^n
= 8 (1)
= 8