integral f(x)= (sin 2x -cos 2x)^2 dx=
Matematika
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Pertanyaan
integral f(x)= (sin 2x -cos 2x)^2 dx=
1 Jawaban
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1. Jawaban DB45
integral trigonometri
∫ (sin 2x - cos 2x)² dx =
= ∫ sin² 2x + cos² 2x - 2 sin 2x cos 2x dx
= ∫ (sin² 2x + cos² 2x) - (2 sin 2x cos 2x)
*ingat sin² A + cos² A = 1
dan 2 sin A cos A = sin 2A*
.
= ∫ 1 - sin 4x dx
= x - 1/4 (- cos 4x) + c
= x + 1/4 cos 4x + c