Pada barisan aritmatika U5-U2=9 U3+U4=29 Tentukan U50 Tolong dijawab pake cara rumus

Bab Barisan dan Deret
Matematika SMP Kelas IX

U5 - U2 = 9
a + 4b - a - b = 9
3b = 9
b = 9/3
b = 3

U3 + U4 = 29
a + 2b + a + 3b = 29
2a + 5b = 29
2a + 5 x 3 = 29
2a = 29 - 15
a = 14 / 2
a = 7

U50 = a + 49b
U50 = 7 + 49 x 3
U50 = 7 + 147
U50 = 154

BARISAN ARITMATIKA

U5 - U2 = 9
(a + 4b) - (a + b) = 9
3b = 9
b = 3

U3 + U4 = 29
(a + 2b) + (a + 3b) = 29
2a + 5b = 29
2a = 29 - 5b
2a = 29 - 5.3
2a = 14
a = 7

U50 = a + 49b = 7 + 49.3 = 154