Jika F'(x) = (x - 2)(x-4) dan F(3) = 1, maka F(x) = ....

f'(x) = (x - 2)(x - 4)
f'(x) = x² - 4x - 2x + 8
f'(x) = x² - 6x + 8

Integralkan

int x² - 6x + 8
= 1/3 (x³) - (6/2) x² + 8x + C
f(x) = 1/3 (x³) - 3x² + 8x + C

1/3 (3³) - 3(3²) + 8(3) + C = 1
1/3 (27) - 3(9) + 24 + C = 1
9 - 27 + 24 + C = 1
6 + C = 1
C = -5


f(x)
= 1/3 (x³) - 3x² + 8x - 5