Jika F' (x) = 3x^2 + 4x dan F(2) = 3, maka F (x) =......

Materi: Integral

F'(x) = 3x^2 + 4x
F(x) = int (3x^2 + 4x) dx
= x^3 + 2x^2 + C
F(2) = 3 = (2)^3 + 2(2)^2 + C
C = 3 - 8 - 8 = -13
Jadi,
F(x) = x^3 + 2x^2 - 13

integral dari 3x²+4x
f(x)= x³+2x²+c
subtitusi f(2)
3 = 2³+2.2²+c
3 = 8+8+c
3= 16+c
3-16 = c
-13 = c

jadi persamaan f(x)
= x³+2x²-13