integral 3x-4x²√x per x√x DX

integral tak tentu

∫ (3x - 4x²√x) / (x√x) dx =
= ∫ (3x - 4x². x¹/²) / (x. x¹/²)  dx
= ∫  (3x - 4x⁵/²)  / (x³/²) dx
= ∫ (3x - 4x⁵/²) (x⁻³/²) dx
 = ∫  3x (x⁻³/²)   - 4x⁵/² (x⁻³/²)
= ∫ 3x⁻¹/²  - 4 x dx
= 3(2) x¹/² - 4 (1/2)x² + c
= 6 x¹/²  - 2x² + c
= 6√x + 2x² + c