hitunglah panjang CE!

Kesebangunan

ΔABC siku siku di A
BC² = CA² + AB²
BC² = (6+3)² + 12² = 9²+ 12² = 81 + 144= 225
BC = √225 = 15

ΔDEC siku siku di E

ΔCAB ~~ ΔCED
<C = < C
< A = < E
<B = < D

CA/CE = BC/CD
9/ CE = 15/6
CE = 9 x 6 / (15)=  3,6