Matematika

Pertanyaan

Tentukan nilai turunan pertama dari fungsi f(x) = (2x³ - 3)² ; di x = -3

2 Jawaban

  • f(x) = (2x³ - 3)²
    f'(x) = (6x²)(2)(2x³ - 3)¹
    f'(x) = 12x²(2x³ - 3)
    f(-3) = 12(-3²)(2(-3)³ - 3)
    = 12(9)(-57)
    = -6.156
  • Bab Differensial
    Matematika SMA Kelas X

    f(x) = (2x^3 - 3)²
    f' (x) = 2 . (2x^3 - 3) . 6x²
    f' (-3) = 2 . (2 . (-3)^3 - 3) . 6 . (-3)²
    f' (-3) = 2 . (-54 - 3) . 6 . 9
    f' (-3) = -114 . 54
    f' (-3) = -6.156

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