Selesaikan untuk (0 < x < 2pi) A. 2 cos 2x -1 = 0 B. 2 sin²x + 3 sin x = 0
Matematika
rizarahmadani77
Pertanyaan
Selesaikan untuk (0 < x < 2pi)
A. 2 cos 2x -1 = 0
B. 2 sin²x + 3 sin x = 0
A. 2 cos 2x -1 = 0
B. 2 sin²x + 3 sin x = 0
1 Jawaban
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1. Jawaban Anonyme
Bab Trigonometri
Matematika SMA Kelas X
A] 2 cos 2x - 1 = 0
2 cos 2x = 1
cos 2x = 1/2
2x = π/3
x = π/6
2x = 5π/3
x = 5π/6
HP = { π/6, 5π/6 }
2] 2 sin² x + 3 sin x = 0
sin x (2 sin x + 3) = 0
sin x = 0
x = 0
x = π
2 sin x + 3 = 0
2 sin x = - 3
sin x = -3/2 (tidak memenuhi)
HP = { 0, π }