tolong bantu jawab nmr 1 dan 2

Integral Tak tentu

∫ (1 - x² - 5x⁴ ) dx  = ax - b/3 x³ + x⁵ + c
x - 1/3 x³ - x⁵ + c = ax - b/3  x³ + x⁵ + c
x =ax --> a=  1
-1/3 = - b/3 ---> b = 1
a - b = 1 - 1
a - b = 0

2. ∫ (5x⁴ +6x² -1) / (3) dx = ax⁵ - bx³ - dx + c
∫ 5/3 x⁴ - + 2x² - 1/3  dx =
5/3 (1/5) x⁵ + 2/3 x³ - 1/3 x + c = ax⁵ - bx³ - dx + c
1/3 x⁵ + 2/3 x³ - 1/3 x + c = ax⁵ - bx³ - dx + c
a = 1/3
-b =  2/3 --> b = - 2/3
-d = - 1/3 --> d = 1/3

nilai a + b + d = 1/3 -  2/3 + 1/3
a + b + d =  0