Integral (2x-1/x^3)^2 dx

integral

∫ {(2x-1) /(x³)}² dx
= ∫ (2x -1)² /(x³)²  dx
= ∫ (4x² - 4x + 1) / (x⁶) dx
= ∫ (4x² - 4x + 1)(x⁻⁶) dx
= ∫ 4x⁻⁴ - 4x⁻⁵ + x⁻⁶ dx
= 4/ -3 x⁻³  - 4/-4  x⁻⁴ + 1/-5  x⁻⁵ + c
=  -4/(3x³)  + 1/(x⁴) - 1/(5x⁵) + c