Matematika

Pertanyaan

integral x^2 (x+1)^3 dx=

1 Jawaban

  • dijabarin dulu ajah yg pangkat 3
    x^2(x^3 + 3x^2 + 3x + 1) dx
    = (x^5 + 3x^4 + 3x^3 + x^2) dx
    = (1 / 5+1)x^6 + (3 / 4+1)x^5 + (3 / 3+1)x^4 + (1 / 2+1)x^3 + C
    = (1/6)x^6 + (3/5)x^5 + (3/4)x^4 + (1/3)x^3 + C

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