tolong bantu ya kak soalnya besok dikumpulin 240gram urea (CO (NH2)2 dilarutkan dalam 106 gram air. Tentukan fraksi mol urea dan fraksi mol air (Ar N=14, C=12,

mr urea = ( Ar C ) + (ar O) + (4x ar H)+ (2 x ar N)
= 12+16+(4x1)+(2x14)
=60

mr air = (ar O) + (2x ar H)
= 16 + (2x1)
= 18


mol urea = 240 gram/ (60 mol/gram) = 4 mol

mol air = 106 gram/ (18 gram/mol) = 5.88

fraksi mol urea
=mol urea / (mol urea +mol air)
= 4 mol / (4 mol + 5,88 mol)
= 0.45

fraksi mol air
=mol air / (mol urea +mol air)
= 5.88 mol / (4 mol + 5,88 mol)
= 0.595

fraksi mol urea = 0,405
fraksi mol air = 0,595