berapakah x dr persamaan nilai mutlak berikut 1. 2 |3-2x| = 6 2. |1/2x+5| = 0 3. -2 |x+5| = -10 4. 5-3 = |2x-6| 5. |x/3 + 1| + 5 = 5 6. 2 |1-x/2| -3 = 1

Mapel : Matematika
Kelas : X SMA
Bab : Mutlak

Pembahasan :
2|3 - 2x| = 6
|3 - 2x| = 3
(3 - 2x)² = 3²
(3 - 2x)² - 3² = 0
(6 - 2x)(-2x) = 0
-12x + 4x² = 0
4x² - 12x = 0
x² - 3x = 0
x(x - 3) = 0
x = 0
x = 3

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|1/2x + 5| = 0
1/2x + 5 = 0
1/2x = -5
x = -10

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-2|x + 5| = -10
|x + 5| = 5
(x + 5)² - 5² = 0
(x + 10)(x) = 0
x² + 10x = 0
x(x + 10) = 0
x = 0
x = -10

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5 - 3 = |2x - 6|
|2x - 6| = 2
(2x - 6)² - 2² = 0
(2x - 4)(2x - 8) = 0
x = 2
x = 4

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|x/3 + 1| + 5 = 5
|x/3 + 1| = 0
x/3 + 1 = 0
x/3 = -1
x = -3

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2|1 - x/2| - 3 = 1
2|1 - x/2| = 4
|1 - x/2| = 2
(1 - x/2)² - 2² = 0
(3 - x/2)(-1 - x/2) = 0
x = 6
x = -2