Sifat distributif. 1. 16 (4+2) = 2. 15 (8-3) = 3. 40 (4+6) = 4. 50 (10-5) = 5. 45 (20-18) =
Matematika
Aldakamilah
Pertanyaan
Sifat distributif.
1. 16 (4+2) =
2. 15 (8-3) =
3. 40 (4+6) =
4. 50 (10-5) =
5. 45 (20-18) =
1. 16 (4+2) =
2. 15 (8-3) =
3. 40 (4+6) =
4. 50 (10-5) =
5. 45 (20-18) =
2 Jawaban
-
1. Jawaban novapratiwi19
1. 16 (4+2) = 16(6) = 96
2. 15 (8-3) = 15(5) = 75
3. 40 (4+6) = 40(10) = 400
4. 50 (10-5) = 50(5) = 250
5. 45 (20-18) = 45(2) = 90 -
2. Jawaban bone1
1. 16 (4+2) = (16x4) + (16x2) = 64+32=96
2. 15(8-3) = (15x8) - (15x3) = 120 - 45=75
3. 40(4+6)= (40x4) + (40x6) =160+240=400
4.50(10-5)=(50x10)-(50x5) =500-250=250
5.45(20-18)=(45x20)-(45-18)=900-810=90