Tentukan nilai u,x,y dan z dari: X+2y=5 Y+2z=8 Z+2u=11 Y+2x=6
Matematika
fredrik07
Pertanyaan
Tentukan nilai u,x,y dan z dari:
X+2y=5
Y+2z=8
Z+2u=11
Y+2x=6
X+2y=5
Y+2z=8
Z+2u=11
Y+2x=6
1 Jawaban
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1. Jawaban Sutr1sn0
x + 2y = 5 (×2)
2x + y = 6 (×1)
2x + 4y = 10
2x + y = 6
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3y = 4
y = 4/3
2x + y = 6
2x + 4/3 = 6
2x = 6 - 4/3
2x = 18/3 - 4/3
2x = 14/3
x = (14/3)/2
x = 14/3 × 1/2
x = 14/6
x = 7/3
y + 2z = 8
4/3 + 2z = 8
2z = 8 - 4/3
2z = 24/3 - 4/3
2z = 20/3
z = (20/3)/2
z = 20/3 × 1/2
z = 20/6
z = 10/3
z + 2u = 11
10/3 + 2u = 11
2u = 11 - 10/3
2u = 33/3 - 10/3
2u = 23/3
u = (23/3)/2
u = 23/3 × 1/2
u = 23/6
Jadi nilai u , x , y , dan z adalah 23/6 , 7/3 , 4/3 , dan 10/3