Matematika

Pertanyaan

Tentukan nilai u,x,y dan z dari:
X+2y=5
Y+2z=8
Z+2u=11
Y+2x=6

1 Jawaban

  • x + 2y = 5 (×2)
    2x + y = 6 (×1)
    2x + 4y = 10
    2x + y = 6
    ----------------- -
    3y = 4
    y = 4/3

    2x + y = 6
    2x + 4/3 = 6
    2x = 6 - 4/3
    2x = 18/3 - 4/3
    2x = 14/3
    x = (14/3)/2
    x = 14/3 × 1/2
    x = 14/6
    x = 7/3

    y + 2z = 8
    4/3 + 2z = 8
    2z = 8 - 4/3
    2z = 24/3 - 4/3
    2z = 20/3
    z = (20/3)/2
    z = 20/3 × 1/2
    z = 20/6
    z = 10/3

    z + 2u = 11
    10/3 + 2u = 11
    2u = 11 - 10/3
    2u = 33/3 - 10/3
    2u = 23/3
    u = (23/3)/2
    u = 23/3 × 1/2
    u = 23/6

    Jadi nilai u , x , y , dan z adalah 23/6 , 7/3 , 4/3 , dan 10/3

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