Matematika

Pertanyaan

tentukan nilai u,x,y dan z dari
X+2y=5
Y+2z=8
Z+2u=11
Y+2x=6

1 Jawaban

  • x + 2y = 5
    x = 5 - 2y

    y + 2x = 6
    y + 2(5 - 2y) = 6
    y + 10 - 4y = 6
    -3y = 6-10
    -3y = -4
    y = 4/3

    x = 5 - 2y
    x = 5 - 2(4/3)
    x = 5 - 8/3
    x = 7/3

    y + 2z = 8
    4/3 + 2z = 8
    2z = 8 - 4/3
    2z = 20/3
    z = 20/6
    z = 10/3

    z + 2u = 11
    10/3 + 2u = 11
    2u = 11 - 10/3
    2u = 23/3
    u = 23/6

    maka
    u = 23/6 = 3 5/6
    x = 7/3 = 2 1/3
    y = 4/3 = 1 1/3
    z = 10/3 = 3 1/3

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