Matematika

Pertanyaan

(-4a)³(4a)⅔ per (16a²)⅓

1 Jawaban

  • pangkat ^
    = (-4a)^3 (4a)^⅔ / (4²a²)^⅓
    = (-4^3 a^3) (4^⅔ a^⅔) / (4^2×⅓ a^2×⅓)
    = (-4^3 a^3) (4^⅔ a^⅔) / (4^⅔ a^⅔)
    = -4^3 . a^(3+⅔-⅔) . 4^(⅔-⅔)
    = -4^3 . a^3 . 4^0
    = -4^3 . a^3 .1
    = -64a³

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