dalam 200 gram air dilarutkan 10 gram urea Mr : 60. Kf: 1,86C/molal, ditanya titik beku larutan

p = 200 g
g = 10 g
mr = 60
kf = 1,86 °C/ molal
ditanya = Tf.
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□ Tf = g.1000.kf/mr. p ( gram )
□ Tf = 10.1000. 1,86 / 60.200
□ Tf = 18600/12000
□Tf = 1,55

□ Tf = Tf ° - Tf
Tf = Tf ° - □ Tf
Tf = 0 - 1, 55
Tf = -1,55