1. (3x+1)^4 3 dx 2. (x^2-6)^3 2x dx

integral kan?
1.misal U=3x+1
du/dx = 3
dx = du/3

(3x+1)^4 3 dx
U^4 3 dx
U^4 3 du/3
U^4 du
1/5 U^5 +c
1/5 (3x+1)^5 +c

2.misal U=x^2-6
du/dx = 2x
dx = du/2x

(x^2-6)^3 2x dx
U^3 2x dx
U^3 2x du/2x
U^3 du
1/4 U^4 +c
1/4 (x^2-6)^4 +c

semoga membantuuu