4 gram NaoH dilarutkan dalam 500 air, hitunglah kondisi molalitas

m = gr/mr x v(ml)/1000
= 4/40 x 500/1000
= 0,1 x 0,5
= 0,05 molal

ket: Ar Na 23
Ar O 16
Ar H 1

m = gram naoh/mr x 1000/gram air
= 4/40 x 1000/500
=1/10 x 2
= 2/5
= 0.4