Hubungan kemolaran larutan cuka yang mengandung 24% massa CH3COOH (ar H=1 , C=12 , O=16 )

mr CH3COOH
= (2 x ar C)+ (4 x ar H) + (2x ar O)
= (2x 12) + ( 4 x1) + (2 x 16)
= (24) + (4) + (32)
= 28 + 32
= 60

24 % massa CH3COOH

misalkan massa larutan 100 gram maka
> massa CH3COOH = 24 % X 100 gram = 24 gram
> massa pelarut = 100 gram - 24 gram = 76 gram

jadi
M = 24/60 X 1000/76
= 24000/4560
= 5,2631
= 5,27

jadi konsentrasi molarnya adalah 5,27 M