Dua buah muatan masing-masing 0,001 C dan 0,005 C mengalami gaya tolak menolak . Jika jarak antar muatan 3 meter , berapakah gaya tolak menolak kedua muatan?

q1 = 1 × 10^-3 C
q2 = 5 × 10^-3 C
r = 3 m

Fc = k × q1 × q2/r²
Fc = (9 × 10^9) × (1 × 10^-3) × (5 × 10^-3)/3²
Fc = (9 × 10^9) × (5 × 10^-6)/9
Fc = 45.000/9
Fc = 5.000 N

LISTRIK STATIS
• Gaya

Q1 = 1×10⁻³ C
Q2 = 5×10⁻³ C
r = 3 m
F = __?

gaya listrik
F = k Q1 Q2 / r²
F = 9×10 • 1×10⁻³ • 5×10⁻³ / 3²
F = 5×10³ N = 5000 N ← jwb