integral 4x-8 / √x² -4x+5

Penyelesaian:

∫ 4x - 8 / √x² -4x+5 dx
= ∫ 4x - 8 (x² -4x+5)^-1/2 dx
d(x² -4x+5) = 2x - 4 dx
d(x² -4x+5) / 2x - 4 = dx

∫ 4x - 8 (x² -4x+5)^-1/2 d(x² -4x+5) / 2x - 4
= 1/2 ∫ (x² -4x+5)^-1/2 d(x² -4x+5)
= 1/2 . 2 (x² -4x+5)^1/2
= (x² -4x+5)^1/2
= √x² -4x+5 + c