f'(x)=6x+7 f(2)=26 nomor2. f'(x)=4(x+1) (x-5) f(1)=10

Turunan dan intergral

1)
f ' (x) = 6x + 7
F(2) = 26

F(x) = ∫6x + 7 dx
F(x) = 3x² + 7x + c
F(2) = 26
3(2)² +7(2) + c = 26
12 + 14 + c = 26
c = 0
 F(x) = 3x² + 7x

2)
f '(x) = 4(x+1)(x-5)
f '(x) = 4(x² - 4x - 5)
f '(x) = 4x² -16x - 20
F(x) = ∫(4x² -16x - 20) dx
F(x) = 4/3 x³ -8x² -20x + c
F(1) = 10
4/3 - 8 - 20 + c = 10 ---> kalikan 3
4 - 24 - 60 + 3c = 30
- 80 + 3c = 30
3c = 110
c = 110/3

F(x) = 4/3 x³ -8x² - 20x + 110/3
atau
F(x) = 1/3 ( 4x³ - 24x² -60x +110)