Hasil dari integral (2x-1) (x2-x+3) pangkat 3 adalah.... np: caranya ditulis juga ya..

int (2x - 1)(x² - x + 3)³
misal: u = x² - x + 3
du = 2x - 1 dx
maka
int (2x - 1)(x² - x + 3)³ = int u³ du
= (1/4)u^4 + c
= (1/4)(x² - x + 3)^4 + c

misalkan u = 2x -1 maka [tex] \frac{dx}{du} [/tex] = 2 atau dx = [tex] \frac{1}{2} [/tex] du
[tex]int \frac{1}{2} du = \frac{1}{2} \int\limits \ \frac{1}{2}( {U})^{3}\, du[/tex]
[tex] \frac{1}{4}( x^{2} - x + 3)) ^{3} [/tex] + c
[tex]\frac{4}{4} (x^{2} - x +3) x^{3}[/tex] + c
[tex]( x^{2} - x + 3) ^{4} [/tex] + c.