Nilai lim (x→0) tan² 3x/1 - cos x =.....

= lim x→0, tan²3x / 1-cosx
= lim x→0, tan²3x / 1-(1-2sin²½x)
= lim x→0, tan²3x / 2sin²½x
= lim x→0, (3)² / 2(½²)
= lim x→0, 9 / 2(¼)
= lim x→0, 9/1 ÷ ½
= lim x→0, 18

Lim x->0 (tan^2 3x)/(1-cos x)
Lim x-> 0 (tan^2 3x)/2 sin^2 1/2x
= (3)^2 / 2(1/2)^2
= 9 × 2
= 18