(3/3^×-1)^2=3akar1/9. nilai 8^×?

[tex] (\frac{3}{3 ^{x-1} } ) ^{2} = \frac{3 \sqrt{1} }{9} [/tex]
<=>[[tex][tex] \frac{9}{3 ^({2x-2} )} = \frac{3}{9} [/tex]
kali silang maka diperoleh
<=>81 = [tex] 3^{2x-2} . 3 ^{ \frac{1}{2} } [/tex]
<=> [tex]3^{4} [/tex] = [tex]3^{ ^{ \frac{1}{2}(2x-2) }[/tex]
<=> x - 1 = 4
<=> x = 4+1
           = 5
Nilai [tex]8^{x} [/tex] = [tex]8^{5} [/tex] = 32.768

3^(1 - (x - 1)) = 3^(1 - 1)
3^(2 - x) = 3^0
2 - x = 0
x = 2

8^x = 8^2
= 64